K. Jack vs. Scooter

Started by Jigsaw, August 02, 2013, 12:47:05 PM

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Which one? (Trading Swallow)

K. Jack
8 (57.1%)
S. Selwood
6 (42.9%)

Total Members Voted: 0

Jigsaw

Trading Swallow out this week, but for who?

Had Boydy locked, but now that he's out, I'm looking at the next best.

Do I bring in Scooter (High ceiling, but can be erratic)? Or get back KJack (Traded him out for Beamer, being his form was down and I had the luxury. Looks to be back again).

Thoughts?

Jazzoskies

Personally I have K. Jack so my gut would say pick him.

Scooter will also most likely get the tagging job on Ablett this week, he MIGHT crack down more on keeping Ablett quiet (well as best as one can keep him quiet) which might detract on his scoring output this week? The reason I stress MIGHT is because Scooter seemed to get the job on Griffen last week, but Griffen and Scooter seemed to both ton up.

Jigsaw

Quote from: Jazzoskies on August 02, 2013, 01:30:27 PM
Personally I have K. Jack so my gut would say pick him.

Scooter will also most likely get the tagging job on Ablett this week, he MIGHT crack down more on keeping Ablett quiet (well as best as one can keep him quiet) which might detract on his scoring output this week? The reason I stress MIGHT is because Scooter seemed to get the job on Griffen last week, but Griffen and Scooter seemed to both ton up.

My thoughts as well. Even when Scooter tags, he can still score well. However, I do like Jack's next two games more (Dogs and Pies at ANZ), so will probably look at bringing him back in.

Alka

Jack for the next 2 for sure but I'd say Scooter for the season.

Also consider ROK. Check his record v Pies (for next week). 133 avg from his last 5.

Jigsaw

Quote from: Alka on August 02, 2013, 02:54:58 PM
Jack for the next 2 for sure but I'd say Scooter for the season.

Also consider ROK. Check his record v Pies (for next week). 133 avg from his last 5.

Just had a look at ROK's record. Definitely going to give him some consideration as well.

Have gone with Jack for the time being.