What is everybodies structure

Started by pie time, December 20, 2012, 11:59:11 PM

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pie time

How many prems is needed to start. I think 12 might be short of the mark, but happy with side.

Structure: 5/0/3/0 - 3/1/4/2 - 1/1/2/0 - 3/3/1/1 = 12/5/10/3 (in the format of premium/mid/cheap/rookie for each posi

masedog333

12/5/9/4. mines similar to yours :)

Ringo

here is mine
Structure: 2/2/1/3 - 5/0/3/2 - 1/1/1/1 - 4/0/4/0 = 12/3/9/6 (in the format of premium/mid/cheap/rookie for each position)

Nige

Mine looks like this:

3/1/2/2 - 5/0/4/1 - 1/1/1/1 - 3/1/4/0 = 12/3/11/4 (in the format of premium/mid/cheap/rookie for each position)

dmac07

3/1/4/0 - 5/0/4/1 - 1/1/2/0 - 3/2/3/0 = 12/4/13/1 thought i dont agree with the classification, all the 110k rookies are 'cheap'.

Lozza

4/1/2/1 - 4/1/4/1 - 1/1/1/1 - 4/0/4/0 = 13/3/11/3

Obese Arachnid


Footyrulz

Structure: 3/2/1/2 - 3/2/2/3 - 1/1/1/1 - 4/1/2/1 = 11/6/6/7

Got 1 less premium than most, with a few more bargains.